Question

sin(pi/2+2*x)+cos(pi/2-2*x)=0

Answer 1

sin(pi/2+2*x)+cos(pi/2-2*x)=0

cos 2x+sin 2x=0 |:cos2x; cos2x не равен 0

1+tg2x=0

tg2x=-1

2x=-p/4+pk

x=-p/8+pk/2; k принадлежит Z