Question

Решить неравенство:

$9^{x} - 4$·$3^{x} + 3 leq 0$

Answer 1

9^x-4*3^x+3<=0
3^x=t
t^2-4t+3<=0
D=16-12=4
x12=4+-2/2=1 3
(t-1)(t-3)<=0
============1=======3=======
++++++++++++  -----------   =+++++
t=[1 3]
3^x>=1
x>=0
3^x<=3
x<=1
x=[0 1]