Question

Разложите на множители,оч надо.
xy+3y+xz+3z

25-c^2

ab^2-2abc+ac2

Answer 1

$xy+3y+xz+3z=y(x+3)+z(x+3)=(y+z)(x+3)$
$25-c^2=5^2-c^2=(5-c)(5+c)$
$ab^2-2abc+ac^2 = a(b^2-2bc+c^2)=a(b-c)^2$