Предмет: Алгебра, автор: СладкийСахар

Решите уравнение (x−3) в квадрате (x−4)=30(x−3)  .

Ответы

Автор ответа: mmb1
0
 (x−3) в квадрате (x−4)=30(x−3)  .
x=3 
теперь можно разделить на х-3 так как он уже не равен 0
(x-3)(x-4)=30
x²-7x+12=30
x²-7x-18=0
D=49+72=121
x12=(7+-11)/2=9 -2
x=9
x=-2
ответ -2 3 9
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