Question

{5х-2(у+4)=0
{6(2х+3)-у=41
Помогите 

Answer 1

$left { {{5x-2(y+4)=0} atop {6(2x+3)-y=41}} right. \ \ left { {{5x-2y-8=0} atop {12x-y+18=41}} right. |*(-2) \ \ left { {{5x-2y-8=0} atop {-24x+2y-36=-82}} right. \ \ -19x-44=-82 \ -19x=-82+44 \ -19x=-38 \ x=2 \ 5*2-2y-8=0 \ -2y=-2 \ y=1$