Question

$28^{40}$ и $2^{80}$ * $5^{40}$

Answer 1

$28^{40} = (7*4)^{40} = 7^{40} * 4^{40} \ \ 2^{80}* 5^{40} = (2^{2} )^{40} * 5^{40} = 4^{40} * 5^{40} \ \ 4^{40} * 7^{40} > 4^{40} * 5^{40} \ \ 28^{40} > 2^{80} * 5^{40}$