Question

20 баллов!
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См. Вложение

Answer 1

$sqrt{( sqrt{2}-2 )^2/8} - sqrt{2}/2=(2- sqrt{2})/2 sqrt{2}- sqrt{2}/2= \ 1/ sqrt{2}-1/2- sqrt{2}/2=-1/2$

Answer 2

$sqrt{frac{(sqrt2-2)^2}{8}}-frac{sqrt2}{2}=frac{|sqrt2-2|}{2sqrt2}-frac{sqrt2}{2}=frac{-sqrt2+2}{2sqrt2}-frac{sqrt2}{2}=frac{-sqrt2}{2sqrt2}+frac{2}{2sqrt2}-frac{sqrt2}{2}=\\=-frac{1}{2}+frac{1}{sqrt2}-frac{1}{sqrt2}=-frac{1}{2}$