Question

решите уравнение 2x^2+4x=0

Answer 1

$2 x^{2} +4x=0 \ 2x(x+2)=0 \ 2x=0 \ x_{1}=0 \ x+2=0 \ x_{2} =-2$

Answer 2

2x^2+4x=0 /:2

x^2+2x=0

По теореме Виета:

x1+x2=-2

x1*x2=0

x1=0

x2=-2