Предмет: Химия, автор: Камень01

Найти массу Br2, которая потребуется для получения 50 г 2,4,6 триброманилина. Помогите пожалуйста! !

Ответы

Автор ответа: udodovi

0

хг 50г
C6H5NH2 + 3Br2=C6H2Br3NH2 + 3HBr
480г 330г
х= 480*50/330=72,73г

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