Question

Система уравнений:

x²+y²=x-y

3x-2y=5

Answer 1

$x^2+y^2=x-y\ 3x-2y=5\\ x=frac{5+2y}{3}\\ frac{(5+2y)^2}{9}+y^2=frac{5+2y}{3}-y\\ frac{ 25+20y+4y^2 +9y^2 }{9} = frac{15+6y-9y}{9}\\ 13y^2+20y+25=15-3y\ 13y^2+23y+10=0\ D=23^2-4*13*10=3^2\ y=frac{-23+/-3}{26}=-frac{10}{13};-1\ x=frac{45}{338};1$