Question

(3/7)^3х-7=(7/3)^7х-3

Answer 1

$(3/7)^{3x-7}=(7/3)^{7x-3}\\(3/7)^{3x-7}=(3/7)^{3-7x}\\3x-7=3-7x\3x+7x=3+7\10x=10\x=1$