Question

Найдите производную (y'=..)

Answer 1

$y' = (frac{1}{x^2-2x-8})' = ((x^2-2x-8)^{-1})' =$$-(x^2-2x-8)^{-2} * (x^2-2x-8)' = -(x^2-2x-8)^{-2} * (2x-2) =$$frac{2-2x}{(x^2-2x-8)^2}$