Предмет: Геометрия, автор: roma1994

в прямоугольнике диагональ равна 10,а угол между ней и одной стороной из сторон равен 60°,длина этой стороны равна 5.Найдите площадь.

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Автор ответа: jogger2013

0

прямоугольник ABCD, АС=10, ВС=5, угол ВАС=60, ВС=√(АС в квадрате-АВ в квадрате)=√(100-25)=5*√3, площадь ABCD=АВ*ВС=5*5*√3=25*√3

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