Question

решите пожалуйста очень срочно

Answer 1

б) 3/(х²-4) +1≥0
   (3+х²-4)/(х-2)(х+2)≥0
   (х²-1)/(х-2)(х+2)≥0
   (х-1)(х+1)/(х-2)(х+2)≥0
   
          +                  -                          +                          -                        +
_________-2_____________-1___________1_____________2__________

х∈(-∞;-2)∨[-1;1]∨(2;+∞)

г) 1-(8/x²-1)≥0
   (x²-1-8)/(x²-1)≥0
   (x²-9)/(x-1)(x+1)≥0
   (x-3)(x+3)/(x-1)(x+1)≥0

         +                      -                           +                         -                        +
__________-3____________-1_____________1___________3_______

x∈(-∞;-3]∨(-1;1)∨[3;+∞)

Answer 2

1)
х²-4>0
х²>4
х>2
х<-2

х²-4+3≥0
х²≥1
х≥1
х≤-1
общее решение x>2 и x<-2

х²-4<0
x²<4
x<2
x>-2
х²-4+3≤0
x²-1≤0
x²≤1
x≤1
x≥-1
общее решение
-1≤х≤1
х>2
х<-2
   +                   -                  +                   -                    +
..//////////.-2................-1/////////////////1...................2..///////////////////
точки -2 и 2 вырезаны

2)
х²-1>0
х²>0
х>1
х<-1

х²-1-8≥0
х²-9≥0
х²≥9
х≥3
х≤-3

⇒
x≥3
x≤-3

x2-1<0
x²<1
x<1
x>-1

x²-9≤0
x²≤9
x≤3
x≥-3

общее решение
1-<х<1
x≥3
x≤-3
    +                  -                     +                       -                    +
/////////////-3................-1...////////////////..1....................3//////////////////////
точки 1 и -1 вырезаны