Предмет: Алгебра, автор: Latipovaelvira

Решите задачу. В два сосуда одинаковой массы налита вода, причем масса сосуда А с водой составляет 4/5 массы воды сосуда В с водой. Если воду из сосуда В перелить в сосуд А, то масса его вместе с водой станет 8 раз больше массы сосуда В. Найдите массу сосудов и количество воды в них, если в сосуде В содержится воды на 50 грамм больше.

Ответы

Автор ответа: mrkhomyakovskiy

Пусть Х - масса сосуда, тогда У - масса воды в стакане А. Значит масса воды в сосуде В равна У + 50. Запишем условия задачи в виде системы уравнений. Например,
первое имеет такой вид:
Х + У = 0,8 (Х + У + 50)
Второе:
Х + У+ (У + 50) = 8Х

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