Question

Упростить выражение с решением

$frac{ b^{2} }{xy} + frac{(b+x)^{2} }{ x^{2} -xy} - frac{(b+y)^{2} }{xy-y^{2} }$

Answer 1

$frac{b^{2}}{xy} + frac{(b+x)^{2}} { x^{2} -xy} - frac{(b+y)^{2}}{xy-y^{2}} = \ frac{b^{2}(x-y)+y(b+x)^{2}-x(b+y)^{2}}{xy(x-y)} = \ frac{b^{2}x-b^{2}y+b^{2}y+2bxy+ x^{2} y-b^{2}x-2bxy-y^{2}x}{xy(x-y)}= \ frac{ x^{2} y-y^{2}x}{xy(x-y)}= frac{xy(x-y)}{xy(x-y)} =1$

Answer 2

Спасибо