Question

Lim 3n^2-n+7/6n^2+8n+2

Answer 1

$displaystyle lim_{n to infty}dfrac{3n^2-n+7}{6n^2+8n+2}=lim_{n to infty}dfrac{3-dfrac{1}{n}+dfrac{7}{n^2}}{6+dfrac{8}{n}+dfrac{2}{n^2}}=dfrac{3-0+0}{6+0+0}=dfrac{3}{6}=dfrac{1}{2}$