Question

Помогите решить неравенство:( 
(2х-10)²<x²-26

Answer 1

$(2x-10)^2<x^2-26\\4x^2-40x+100-x^2+26<0\\3x^2-40x+126<0\\frac{D}{4}=20^2-3cdot 126=22\\x_1=frac{20-sqrt{22}}{3},; ; x_2=frac{20+sqrt{22}}{3}\\+ + + + (x_1)- - - -(x_2)+ + + + + +\\xin (frac{20-sqrt{22}}{3};frac{20+sqrt{22}}{3})$