Question

1/6 + (x-3)//4-8x=(x+1)//(2x-1) - (11x-5)//(24x-12)

Answer 1

ОДЗ 2x-1≠0    x≠0,5
$frac{1}{6}+frac{x-3}{4-8x}=frac{x+1}{2x-1}-frac{11x-5}{24x-12} \ frac{1}{6}+frac{x-3}{4(1-2x)}=frac{x+1}{2x-1}-frac{11x-5}{12(2x-1)} \ frac{1}{6}-frac{x-3}{4(2x-1)}=frac{x+1}{2x-1}-frac{11x-5}{12(2x-1)} \ frac{2-3(x-3)}{12(2x-1)}=frac{12(x+1)-(11x-5)}{12(2x-1)} \ 2-3x+9=12x+12-11x+5 \ -3x+11=x+17 \ -4x=6 \ x=-1,5$