Предмет: Геометрия, автор: ArthurXD

Через высоту трапеции , лежащей в основании прямой призмы , проведено сечение , площадь которого равна 120 см^2.Определите объем призмы , если стороны трапеции равны 12 см , 13 см , 22 см и 13 см.

Ответы

Автор ответа: tyrin
0
Решение:
Vпр=Sосн * H
Основание прямой призмы - равнобедренная трапеция
H-высота призмы
Sосн=(a+b)*h/2
h-высота трапеции
a=22
b=12
h²=13²-((a-b)/2)²=13²-5²=12²
13-длина боковой стороны трапеции
h=12
Sc=h*H=
120=12*H
H=10
Vпр=(22+12)*12/2 * 10=2040 cm³
Ответ:Vпр=2040cm³


Автор ответа: tyrin
0
Вопросы?
Автор ответа: ArthurXD
0
нет вопросов,разве что большой респект!!!
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