Предмет: Математика, автор: Аноним

в 8 часов утра из города а в город б вышел автобус со скоростью 56 км ч а в 11 часов дня из б в а вышел грузовик со скоростью32 км ч в какое и на каком расстояние от города а они встретились если расстояние между городами 520 км

Ответы

Автор ответа: Alenca2000
0
К моменту выезда грузовика автобус уже проехал 3 часа. т. е. 168 км.
Т. е. между ними остается 520-168=352 км.

Скорость сближения 56+32=88 км/ч.
Следовательно встретятся они через 4 часа (352/88).
За 4 часа автобус проедет 4*56=224 км.

Прибавляем к этому уже пройденные им 168 км. Получаем 224+168=392.

Ответ. 392 километра. 
Автор ответа: katia217
0
11 - 8 = 3 часа32 * 3 = 96 км56 - 32 = 24 км/ч скорость сближения96 : 24 = 4 часа11 + 4 = 15 : 0056 * 4 = 224 км от города А
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