Question

5Х²+20x=0

5Х²-8x+3=0

x(x-1)

-------------=0

(x-1)(x-2)

Answer 1

$x(5x-20)=0 \ x=0; 5x-20=0 \ 5x=20 \ x=4 \ 5x^2-8x+3=0 \ D= 64-60 \ sqrt{D}=sqrt{4}=2 \ x_1= frac{8+2}{10}=1 \ x_2= frac{8-2}{10}= frac{3}{5} \ frac{x-(x-1)}{(x-1)(x-2)}=0 \ frac{x}{x-2}=0 \ left { {{x=0} atop {x-2neq0}} right \ left { {{x=0} atop {xneq2}} right$