Question

$log7 (x-1)=log _{7}2+log _{7} 3$

Answer 1

Одз : x>1
$log _{7} (x-1)=log _{7} 2+log _{7}3 \ log _{7}(x-1)=log _{7}(2*3) \ log _{7}(x-1)=log _{7}6 \ x-1=6 \ x=7$
Ответ:x=7