Question

Решите систему уравнений 2х^2у-у=7 ху-х+3у-3=0

Answer 1

$left { {{2x^2y-y=7} atop {xy-x+3y-3=0}} right$

 

$left { {{2x^2y-y=7} atop {(y-1)(x+3) = 0}} right$

 

$left [ {{ left { {{2x^2y-y=7} atop {x = -3}} right atop left { {{2x^2y-y=7} atop { y = 1}} right right$

 

$left [ {{ left { {{2*9y-y=7} atop {x = -3}} right atop left { {{2x^2-1=7} atop { y = 1}} right right$

 

$left [ {{ left { {{y=7/17} atop {x = -3}} right atop left { {{x =pm 2} atop { y = 1}} right right$

 

Ответ: (-3, 7/17), (-2, 1), (2, 1)