Question

(2 3/9-1 7/9)+6 4/9-(4 2/9+8/9)=
столбиком

Answer 1

$(2 frac{3}{9} -1 frac{7}{9} )+6 frac{4}{9} -(4 frac{2}{9} + frac{8}{9} )=1 frac{8}{9} \ \ 1) 2 frac{3}{9} -1 frac{7}{9} =1 frac{12}{9} -1 frac{7}{9} = frac{5}{9} \ \ 2)4 frac{2}{9} + frac{8}{9} =4 frac{10}{9} =5 frac{1}{9} \ \ 3) frac{5}{9} +6 frac{4}{9} =6+1=7 \ \ 4) 6 frac{9}{9} -5 frac{1}{9} =1 frac{8}{9}$