Question

Решить уравнение:
$log_{x}2- log_{4}x+7/6=0$

Answer 1

$log_x2-log_4x+dfrac76=0\ dfrac1{2log_4x}-log_4x+dfrac76=0\ log_4x=u;;dfrac1{2u}-u+dfrac76=0\ 6u^2-7u-3=0\ D=49+72=121=11^2\ u=dfrac{7pm11}{12}\ u_1=dfrac32quad u_2=-dfrac13\ log_4xinleftlbracedfrac32;-dfrac13rightrbrace\ xinleftlbrace8;dfrac1{sqrt[3]4}rightrbrace$