Question

1074(2,4), РЕШИТЕ ПОЖАЛУЙСТА!!!!

Answer 1

$1074.;2);-sin(pi-alpha)+tg(alpha-pi)-cosleft(fracpi2+alpharight)=\=-sin(pi-alpha)-tg(pi-alpha)-cosleft(fracpi2+alpharight)=-sinalpha+tgalpha-sinalpha=\=tgalpha-2sinalpha=frac{sinalpha}{cosalpha}-2sinalpha=frac{sinalpha-2sinalphacosalpha}{cosalpha}=frac{sinalpha-sin2alpha}{cosalpha}$
$4);cosbetacdot tg(pi+beta)cdot tgleft(frac{3pi}2-betaright)cdot cosecleft(fracpi2-betaright)=\=cosbetacdot tg(pi+beta)cdot tgleft(frac{3pi}2-betaright)cdotfrac1 {sinleft(fracpi2-betaright)}=\=cosbetacdot tgbetacdot ctgbetacdotfrac1{cosbeta}=1$