Question

Преобразуйте выражение в многочлен: 

(6m+7)^2=
(4z+5/8)^2=
(3/5-3x)^2=
(-7a+3b)^2=
(0,9b-5c)^2=
(2/3x-3/2y)^2=

Answer 1

$(6m+7)^{2}=36m^{2}+84m+49$
$(4z+ frac{5}{8})^{2}=16z^{2}+5z+ frac{25}{64}$
$( frac{3}{5}-3x)^{2}= frac{9}{25}- frac{18}{5}x+9 x^{2}$
$(-7a+3b)^{2}=49a^{2}-42ab+9b^{2}$
$(0.9b-5c)^{2}=0.81b^{2}-9bc+25c^{2}$
$( frac{2}{3}x- frac{3}{2}y)^{2}= frac{4}{9}x^{2} -2xy+ frac{9}{4}y^{2}$

Answer 2

(6m+7)^2=36m^2+84m+49=120m+49 (3/5-3x)^2=0,36-1,08x+9x^2 (-7a+3b)^2=49a^2-42ab+9b^2 (0,9b-5c)^2=0,81b^2-9bc+25c^2