Question

решите уравнение (x+3)^2-16=(1-2x)^2 

Answer 1

$( x+3)^{2}-16= (1-2x)^{2}$
$x^{2} +6x+9-16=1-4x+4 x^{2}$
$x^{2} +6x-7=4 x^{2} -4x+1$
$x^{2} -4 x^{2} +6x+4x-7-1=0$
$-3 x^{2} +10x-8=0$
$D= 10^{2}-4*(-3)*(-8)=100-96=4$
$x_{1} = frac{-10- sqrt{4} }{2*(-3)}= frac{-10-2}{-6}= frac{-12}{-6}=2$
$x_{2}= frac{-10+2}{-6}= frac{-8}{-6}=4/3$
Ответ:(2;4/3)

Answer 2

x^2+6x+9-16=1-4x+4x^2
-3x^2+10x-8=0
k=5
дискриминант=25-24=1
x1,2=(5+-1)/6
x1=2
x2=4/3