Question

Решите уравнение |cosx|=sinx

Answer 1

|cosx|≥0 => |cosx|=cosx
cosx=sinx
1=tgx

$x= frac{ pi }{4} +2 pi k$


|cosx|<0 => |cosx|=-cosx
-cosx=sinx
-1=tgx

$x= frac{3 pi }{4} +2 pi k$