Question

Решите уравнение

y^3+3y^2-y-3=0

Answer 1

y^3 + 3y^2 - y - 3=0
y^3 + y^2 + 2y^2 + 2y - 3y - 3 = 0
y^2(y + 1) + 2y (y + 1) - 3(y+1) = 0
(y+1)(y^2 + 2y - 3) = 0
(y+1)(y^2 - y + 3y - 3) = 0
(y+1)(y(y - 1)+3(y - 1)) = 0
(y+1)(y+3)(y-1) = 0
y = -1, y = -3, y = 1.

Ответ:-3, -1, 1.