Question

lg10+lgx=lg(a-b)-lgb

Answer 1

lg10+lgx=lg(a-b)-lgb 10x=(a-b)/b x=(a-b)/(10*b)

Answer 2

lg10+lgx=lg(a-b)-lgb; lg(10x)=lg((a-b)/b) 10x=a-b)/b; x=a-b)/10b; ОДЗ: x>0, a>b, b>0