Question

помогите 4sin 2 x cos 2x = 1

Answer 1

$4sin2xcos2x=1;\ 2cdot2cdotsin2xcdotcos2x=1;\ 2cdotsin4x=1;\ sin4x=frac{1}{2};\ 4x=(-1)^ncdotarcsinfrac{1}{2}+pi n=(-1)^ncdotfrac{pi}{6}+pi n, nin Z\ x=(-1)^ncdotfrac{pi}{24}+frac{pi n}{4}, nin Z$