Question

2. Запишите в виде несократимой обыкновенной дроби: a) 0,(3); 6) 0,(6); г) 0,(28); д) 0,(19); Ответы: 1 в) 0,(12); e) 0,(21). 2 4 28 19 7 а) a) 3; б) 3; в) 33 ; г) 99 ; д) 99 ; е) 33 .​

Answer 1

Ответ:

a) \( 0,(3) = \frac{1}{3} \)

б) \( 0,(6) = \frac{2}{3} \)

в) \( 0,(28) = \frac{28}{99} \)

г) \( 0,(19) = \frac{19}{99} \)

д) \( 0,(12) = \frac{4}{33} \)

е) \( 0,(21) = \frac{7}{33} \)

Объяснение:

# Correcting the mistake in the previous code to accurately convert repeating decimals to fractions

def convert_repeating_decimal_to_fraction(decimal_str):

# Find the length of the repeating sequence

repeat_len = len(decimal_str) - 2 # subtracting 2 to account for '0.' part

# Convert the repeating decimal to a fraction

numerator = int(decimal_str[2:]) - int(decimal_str[2]) // 10

denominator = 10**repeat_len - 1

return Fraction(numerator, denominator)

# Apply the function to each provided repeating decimal

repeating_decimals = ['0.(3)', '0.(6)', '0.(28)', '0.(19)', '0.(12)', '0.(21)']

fractions = [convert_repeating_decimal_to_fraction(d.replace('(', '').replace(')', '')) for d in repeating_decimals]

fractions