Question

2x² +8x-10=0; х²+х-30=0
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Answer 1

1)2х^2+8х-10=0 |:2
х^2+4х-5=0
d=16-4*(-5)=16+20=36
√d= √36=6
x1=(-4-6)/2=-5
x2=(-4+6)/2=1

2)x^2+x-30=0
x1x2=-30
x1+x2=-1

x1=-6
x2=5