Question

433.° Перетворіть у многочлен вираз: 1) (a + b) (c – d);
6) (3y – 5) (2y – 12);
2) (x – 6) (x – 4);
7) (2x2 – 3) (x2 + 4);
3) (a – 3) (a + 7);
8) (x – 6) (x2 – 2x + 9);
4) (11 – c) (c + 8);
9) (5x – y) (2x2 + xy – 3y2);
5) (d + 13) (2d – 1);
10) b (6b + 7) (3b – 4).

Пж срочно!

Answer 1

Відповідь:

1) (a + b) (c – d) = ac - ad + bc - bd

2) (x – 6) (x – 4) = x^2 - 4x - 6x + 24 = x^2 - 10x + 24

3) (a – 3) (a + 7) = a^2 + 7a - 3a - 21 = a^2 + 4a - 21

4) (11 – c) (c + 8) = 11c + 88 - c^2 - 8c = -c^2 + 3c + 88

5) (d + 13) (2d – 1) = 2d^2 - d + 26d - 13 = 2d^2 + 25d - 13

6) (3y – 5) (2y – 12) = 6y^2 - 36y - 10y + 60 = 6y^2 - 46y + 60

7) (2x^2 – 3) (x^2 + 4) = 2x^4 + 8x^2 - 3x^2 - 12 = 2x^4 + 5x^2 - 12

8) (x – 6) (x^2 – 2x + 9) = x^3 - 2x^2 + 9x - 6x^2 + 12x - 54 = x^3 - 8x^2 + 21x - 54

9) (5x – y) (2x^2 + xy – 3y^2) = 10x^3 + 5x^2y - 2xy^2 - 15xy + 5y^2 = 10x^3 + 5x^2y - 15xy - 2xy^2 + 5y^2

10) b (6b + 7) (3b – 4) = 18b^2 - 24b + 42b - 56 = 18b^2 + 18b - 56

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