Предмет: Физика, автор: evaom100

Щоб розтопити лід знадобилося 6.8×10^5 Дж енергії. Яка маса льоду? (3.4 ×10^5 джоулів енергії - ג льоду, питома теплота плавлення) Всі дані при температурі нуль градусів.

З поясненням!

Ответы

Автор ответа: 00morg00

Масу льоду можна знайти, поділивши кількість енергії на питому теплоту плавлення:

m = Q / λ

m = 6,8 * 10^5 / 3,4 * 10^5 = 6,8 / 3,4 = 2 (кг)

Відповідь: m = 2 кг

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