Question

ПОМОГИТЕ ППЖПЖПЖПЖПЖПЖПЖПЖПЖПЖ

Answer 1

Ответ:

Решить систему уравнений . Сложим первое уравнение со вторым и вычтем .

$\left\{\begin{array}{l}\bf x^2y^3+x^3y^2=12\\\bf x^2y^3-x^3y^2=4\end{array}\right\ \oplus \ominus \ \left\{\begin{array}{l}\bf 2x^2y^3=16\\\bf 2x^3y^2=8\end{array}\right\ \ \left\{\begin{array}{l}\bf x^2y^3=8\\\bf x^3y^2=4\end{array}\right$  

$\left\{\begin{array}{l}\bf y^3=\dfrac{8}{x^2}\\\bf x^3\cdot \sqrt[3]{\bf \dfrac{64}{x^4}}=4\end{array}\right\ \ \left\{\begin{array}{l}\bf y=\sqrt[3]{\bf \dfrac{8}{x^2}}\\\bf 4\cdot x^{\frac{8}{3}}=4\end{array}\right\ \ \left\{\begin{array}{l}\bf y=\sqrt[3]{\bf \dfrac{8}{x^2}}\\\bf x^{\frac{8}{3}}=1\end{array}\right\ \ \left\{\begin{array}{l}\bf y=\sqrt[3]{\bf 8}\\\bf x=1\end{array}\right\\\\\\\left\{\begin{array}{l}\bf y=2\\\bf x=1\end{array}\right$