Question

сократите дробь 3^2n+5*2^n-1/18^n+1

Answer 1

$frac{3^{2n+5}*2^{n-1}}{18^{n+1}}=frac{3^{2n+5}*2^{n-1}}{3^{2(n+1)}*2^{n+1}}=3^{2n+5-2n-2}*2^{n-1-n-1}=$$3^3*2^{-2}=frac{27}{4}$