Question

решите систему уравнений 2x+y^2=4; x-y=2

Answer 1

Ответ: (2;0), (0;-2).

Объяснение:

$\displaystyle\\\left \{ {{2x+y^2=4} \atop {x-y=2}} \right. \ \ \ \ \ \ \ \left \{ {{2*(y+2)+y^2=4} \atop {x=y+2}} \right. \ \ \ \ \ \ \left \{ {{2y+4+y^2=4} \atop {x=y+2}} \right.\ \ \ \ \ \ \left \{ {{y^2+2y=0} \atop {x=y+2}} \right. \\\\\\\left \{ {{y*(y+2)=0} \atop {x=y+2}} \right.\ \ \ \ \ \ \ \ \left \{ {{y_1=0\ \ \ \ y_2=-2} \atop {x_1=2\ \ \ \ x_2=0}} \right. .$