Question

СРОЧНО!!!!!!!!

Розв'яжи систему нерівностей

Фото знизу

Answer 1

$\displaystyle\bf\\\left \{ {{12x+15\geq 8(x+1)-5} \atop {\dfrac{2x-7}{3} < \dfrac{3x-11}{5} +1}} \right. \\\\\\\left \{ {{12x+15\geq 8x+8-5} \atop {\dfrac{2x-7}{3} \cdot 15 < \dfrac{3x-11}{5} \cdot 15+1\cdot 15}} \right. \\\\\\\left \{ {{12x-8x\geq 3-15} \atop {(2x-7)\cdot 5 < (3x-11)\cdot 3+15}} \right. \\\\\\\left \{ {{4x\geq -12} \atop {10x-35 < 9x-33+15}} \right. \\\\\\\left \{ {{x\geq -3} \atop {10x-9x < -18+35}} \right. \\\\\\\left \{ {{x\geq -3} \atop {x < 17}} \right.$

$\displaystyle\bf\\Otvet \ : \ x\in\Big[-3 \ ; \ 17\Big)$