Предмет: Химия, автор: anagrisanova12

10,4 г алкіну приєднує 8,96 л водню. Визначити формулу алкіну.​

Ответы

Автор ответа: dyexfnf
2

Ответ:

Объяснение:

Дано:

m(СₙH₂ₙ-₂) = 10,8 г

V(H₂) = 8,96 л

Найти: СₙH₂ₙ-₂ - ?

Складемо РХР:

 10,8 г        8,96 л

СₙH₂ₙ-₂  +     2H₂ =  CₙH₂ₙ₊₂

    х г          44,8 л

х = 10,8 * 44,8 : 8,96 = 54 г

Підставимо у формулу молярну масу

12n + 2n- 2 = 54

14n - 2 = 54

14n = 54 + 2

14n = 56

n = 56 : 14

n = 4

Формула алкіну: С₄Н₆ - бутин

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