Question

(-⅔a-⁴ b-⁸)-² * (⅑ a-⁵ b¹²)

Answer 1

Ответ:

${( - \frac{2}{3} {a}^{ - 4} {b}^{ - 8} )}^{ - 2} \times ( \frac{1}{9} {a}^{ - 5} {b}^{12} ) = \frac{1}{ {( - \frac{ 2}{3} {a}^{ - 4} {b}^{ - 8} )}^{2} } \times ( \frac{1}{9} {a}^{ - 5} {b}^{12} ) = \frac{ \frac{1}{9} {a}^{ - 5} {b}^{12} }{\frac{4}{9} {a}^{ - 8} {b}^{ - 16} } = \frac{1}{4} {a}^{3} {b}^{28}$