Question

ПОМОГИ ППЖПЖПЖПЖПЖПЖПЖПЖ

Answer 1

$\displaystyle\bf\\:\left \{ {{x^{2} y^{3} =81} \atop {x^{3} y^{2}=3 }} \right.\\ ------\\\\\frac{x^{2}y^{3} }{x^{3} y^{2} } =\frac{81}{3} \\\\\\\frac{y}{x} =27 \ \ \ \Rightarrow \ \ \ y=27x\\\\\\x^{3} y^{2} =3\\\\x^{3} \cdot(27x)^{2} =3\\\\x^{3} \cdot 729x^{2} =3\\\\729x^{5} =3\\\\x^{5} =\frac{1}{243} \\\\\\x=\sqrt[5]{\frac{1}{243} } =\frac{1}{3} \\\\\\y=27x=27\cdot\frac{1}{3} =9\\\\\\Otvet \ : \ \Big(\frac{1}{3} \ ; \ 9\Big)$