Question

найти корни уравнения 3х^2+|х| -10=0 |

Answer 1

Ответ:

x = ±$1\frac{2}{3}$

Объяснение:

$3x^2+|x|-10=0\\|x|=t\geq 0\\3t^2+t-10=0\\t_{1,2}= \frac{-1+-\sqrt{1^2-4*3*(-10)} }{2*3} = \frac{-1+-11}{6} =(1\frac{2}{3};-2)\\\\\textbf{1)}\ t = 1\frac{2}{3}\\ |x| =1 \frac{2}{3} \\x=+-1\frac{2}{3} \\\\\textbf{2)}\ t = -2\\|x| = -2\\\text{no solution}$