Question

Дам 100 балов но срочно!​

Answer 1

Ответ:

................

Объяснение:

...................

Answer 2

$\displaystyle\bf\\\Big(\frac{b+1}{b-1} -\frac{b-1}{b+1} \Big)\cdot\frac{b^{2} -1}{8b} =\frac{1}{2} \\\\\\\frac{(b+1)\cdot(b+1)-(b-1)\cdot(b-1)}{(b-1)\cdot(b+1)}\cdot\frac{b^{2} -1}{8b}=\frac{1}{2} \\\\\\\frac{b^{2} +2b+1-b^{2} +2b-1}{b^{2}-1 } \cdot\frac{b^{2} -1}{8b} =\frac{1}{2} \\\\\\\frac{4b}{8b} =\frac{1}{2} \\\\\\\frac{1}{2} =\frac{1}{2}$