Предмет: Химия, автор: oleksandrafrenksi

14. Елемент VI групи утворює оксид у якому масова частка невідомого елемента
0,622. Визначте елемент, складiть формулу сполуки, установіть вид хімічного
зв'язку, тип кристалічноï гратки.

14 завдання будь ласка

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Ответы

Автор ответа: dyexfnf
0

Ответ:

Объяснение:

Формула вищого оксиду VІ групи  - ЕО₃

Знаходимо масову частку Оксигену:

w(О) = 1 - w(Е) = 1 - 0,622 = 0,378

Визначаємо масу Оксигену, виходячи з загальної формули, в 1 моль:

m(O) = 3 * 16 = 48 г

Складаємо пропорцію:

48 г (О) - 0,378

х г (Е) - 0,622

0,378 х = 48 * 0,622

0,378 х = 29,856

х = 29,856 : 0,378

х = 79

Отже, це - Селен, елемент головної підгрупи VІ групи з відносною атомною масою 79

Формула спрлуки : SeO₃ ковалентний полярний хімічний зв'язок

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