Question

на фото розклади на множники:

Answer 1

$0.2mn {}^{3} - 1.5m {}^{2} + 0.6m {}^{3} n - 0.5n {}^{2} \\ \\ \frac{1}{5 } \ mn {}^{3} - \frac{3}{2} m {}^{2} + \frac{3}{5} m {}^{3} n - \frac{1}{2} n {}^{2} \\ \\ \\ \frac{1}{10} \times (2mn {}^{3} - 15m {}^{2} + 6m {}^{3} n - 5n {}^{2} ) \\ \\ \frac{1}{10} \times (2mn \times (n {}^{2} + 3m {}^{2} ) - 5(3m {}^{2} + n {}^{2} )) \\ \\ \frac{1}{10} \times (n {}^{2} + 3m {}^{2} ) \times (2mn - 5)$