Предмет: Алгебра, автор: Safari0sar

Разложите на множители:
1) 56а¹⁰b⁶-32a⁴b⁸
2)36mn⁵+63m²n⁶

Ответы

Автор ответа: eeseooes
0

Объяснение:

1) 56а¹⁰b⁶-32a⁴b⁸ = 8a⁴b⁶ • (7a⁶ - 4b²)

2)36mn⁵+63m²n⁶ = 9mn⁵ • (4 + 7mn)

Автор ответа: litoninasofia
1

Ответ:

1) 56a¹⁰b^⁶ - 32a⁴ b^⁸

Разложим числители 56 и 32 на их простые множители:

56 = 2³×7

32 = 2⁵

Теперь разложим каждый моном:

56a^¹⁰b⁶= 2³ ×7 × a¹⁰ b⁶

32a⁴b⁸ = 2⁵× a⁴ ×b⁸

Теперь вынесем общие множители:

56a¹⁰b⁶ - 32a⁴b⁸ = 2³×7 ×a⁴b⁶ ×(7a⁶ - 4b²)

2) 36mn⁵ + 63m²n⁶

Разложим числители 36 и 63 на их простые множители:

36 = 2²× 3²

63 = 3² ×7

Теперь разложим каждый моном:

36mn⁵ = 2²×3² m ×n⁵

63m²n⁶ = 3²×7 m²n⁶

Теперь вынесем общие множители:

36mn⁵+ 63m²n⁶ = 3² × m × n⁵×(4 + 7m)

Объяснение:

надеюсь помогла

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