Question

3. X-9 x+1 x + 3 1-X X 8 2 -1​

Answer 1

Ответ:

$\frac{x - 9}{x + 1} - \frac{x + 3}{1 - x} - \frac{8}{ {x}^{2} - 1 } = 0 \\ \frac{(x - 9)(x - 1) + ( x + 3)(x + 1) - 8}{(x - 1)(x + 1)} = 0 \\ \frac{ {x}^{2} - x - 9x + 9 + {x}^{2} + x + 3x + 3 - 8} {(x - 1)(x + 1)} = 0 \\ \frac{ 2{x}^{2} - 6x + 4 }{(x - 1)(x + 1)} = 0 \\ \frac{2( {x}^{2} - 3x + 2) }{(x - 1)(x + 1)} = 0 \\ {x}^{2} - 3x + 2 = 0 \\ {x}^{2} - 3x = - 2$

Объяснение:

извини дальше не знаю